# Heading
Tags: algorithms array dynamic-programming
Langs: c cpp csharp dart elixir erlang golang java javascript kotlin php python python3 racket ruby rust scala swift typescript
- algorithms
- Medium (70.07%)
- Likes: 1656
- Dislikes: -
- Total Accepted: 579.7K
- Total Submissions: 826.1K
- Testcase Example: '[[1,3,1],[1,5,1],[4,2,1]]'
给定一个包含非负整数的 m x n
网格 grid
,请找出一条从左上角到右下角的路径,使得路径上的数字总和为最小。
说明:每次只能向下或者向右移动一步。
示例 1:

输入:grid = [[1,3,1],[1,5,1],[4,2,1]] 输出:7 解释:因为路径 1→3→1→1→1 的总和最小。
示例 2:
输入:grid = [[1,2,3],[4,5,6]] 输出:12
提示:
m == grid.length
n == grid[i].length
1 <= m, n <= 200
0 <= grid[i][j] <= 200
/*
* @lc app=leetcode.cn id=64 lang=javascript
*
* [64] 最小路径和
*/
// @lc code=start
/**
* @param {number[][]} grid
* @return {number}
*/
var minPathSum = function (grid) {
const m = grid.length
const n = grid[0].length
const dp = []
for (let i = 0; i < m; i++) {
dp[i] = []
dp[i][0] = i > 0 ? grid[i][0] + dp[i - 1][0] : grid[i][0]
}
for (let i = 1; i < n; i++) {
dp[0][i] = grid[0][i] + dp[0][i - 1]
}
for (let i = 1; i < m; i++) {
for (let j = 1; j < n; j++) {
dp[i][j] = Math.min(dp[i - 1][j], dp[i][j - 1]) + grid[i][j]
}
}
return dp[m - 1][n - 1]
}
// @lc code=end
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33